For the first parabola, \( y^2 - 4x - 8y + 40 = 0 \):
- Rearranging gives \( y^2 - 8y + 40 = 4x \).
- Completing the square for \( y \):
\[
y^2 - 8y = (y - 4)^2 - 16 \implies (y - 4)^2 - 16 + 40 = 4x \implies (y - 4)^2 = 4x - 24.
\]
- Thus, the first
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