Question
The shortest distance between line $y-x=1$ and curve $x=y^{2}$ is(A) $\frac{4}{\sqrt{3}}$(B) $\frac{\sqrt{3}}{4}$(C) $\frac{3 \sqrt{2}}{8}$(D) $\frac{8}{3 \sqrt{2}}$
Step 1
Since the line $y-x=1$ has a slope of 1, the tangent to the curve $x=y^{2}$ will also have a slope of 1. Show more…
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