Question
The motion of a body is depicted graphically as shown in the figure, then the average speed of the bo is $\mathrm{m} _\mathrm{s} ^{-}$(1) $\frac{3}{4}$(2) $\frac{9}{8}$(3) $\frac{4}{3}$(4) $\frac{8}{9}$
Step 1
This can be represented mathematically as: \[ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} \] Show more…
Show all steps
Your feedback will help us improve your experience
Darshan Maheshwari and 83 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The figure shows the position of an object as a function of time, with all numbers accurate to two significant figures. Between time t = 0 s and t = 9 s, what is the average speed and average velocity of the object?
From the graph:h The total distance moved by the body $=\mathrm{OB}+\mathrm{BC}+\mathrm{CD}+\mathrm{DE}+\mathrm{EF}$ $=6+(6-3)+(8-3)+(9-8)+(12-9)$ $=6+3+5+1+3$ $=18 \mathrm{~m}$ Total time taken $(\mathrm{t})=16 \mathrm{~s}$ Average speed $=\frac{\text { total distance }}{\text { total time }}=\frac{18}{16} \mathrm{~m} \mathrm{~s}^{-1}=9 / 8 \mathrm{~m} \mathrm{~s}^{-1}$
The displacement versus time for a certain particle moving along the $x$ axis is shown in Figure $\mathrm{P} 2.3 .$ Find the average velocity in the time intervals (a) 0 to $2 \mathrm{~s}$, (b) 0 to $4 \mathrm{~s}$, (c) $2 \mathrm{~s}$ to $4 \mathrm{~s}$, (d) $4 \mathrm{~s}$ to $7 \mathrm{~s}$, (e) 0 to $8 \mathrm{~s}$.
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD