The motion of a particle of a mass m is describe by y=ut+(1 / 2) gt^2. Find the force acting on

Name: Problem 400, Chapter 3: JEE Physics
Uploaded: 2021-09-30T21:15:26-08:00
Duration: 2 min 53 s
Channel: Vysakh M
Description: The motion of a particle of a mass m is describe by y=ut+(1 / 2) gt^2. Find the force acting on the particle. (A) F=ma (B) F=mg (C) F=0 (D) None of these

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Question

The motion of a particle of a mass $m$ is describe by $\mathrm{y}=\mathrm{ut}+(1 / 2) \mathrm{gt}^{2}$. Find the force acting on the particle. (A) $\mathrm{F}=\mathrm{ma}$ (B) $\mathrm{F}=\mathrm{mg} \quad$ (C) $\mathrm{F}=0$ (D) None of these

    The motion of a particle of a mass $m$ is describe by $\mathrm{y}=\mathrm{ut}+(1 / 2) \mathrm{gt}^{2}$. Find the force acting on the particle.
(A) $\mathrm{F}=\mathrm{ma}$
(B) $\mathrm{F}=\mathrm{mg} \quad$ (C) $\mathrm{F}=0$
(D) None of these

JEE Physics

StemEZ 1st Edition

Chapter 3, Problem 400

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Solved by Expert Vysakh M

09/30/2021

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We need to find the acceleration 'a' from this equation. Show more…

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The motion of a particle of a mass $m$ is describe by $\mathrm{y}=\mathrm{ut}+(1 / 2) \mathrm{gt}^{2}$. Find the force acting on the particle. (A) $\mathrm{F}=\mathrm{ma}$ (B) $\mathrm{F}=\mathrm{mg} \quad$ (C) $\mathrm{F}=0$ (D) None of these

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Key Concepts

Kinematics of Uniformly Accelerated Motion

This concept deals with the motion of objects that experience constant acceleration. The equation y = ut + 1/2 gt² is a standard kinematic formula used to calculate the displacement of an object when it starts with an initial velocity and is subjected to a uniform acceleration, such as gravity.

Newton's Second Law

This principle states that the force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). It is a fundamental concept in mechanics that relates the net force applied on a body to the rate of change of its momentum, allowing for the calculation of forces based on observed accelerations.

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