Question
The motion of particle of mass $m$ is given by $y=u t+\frac{1}{2} g t^{2}$, The force acting on the particle is(a) $m g$(b) $\frac{m u}{t}$(c) $2 m g$(d) $\frac{2 m u}{t}$
Step 1
This equation gives the position of the particle at any time $t$. Show more…
Show all steps
Your feedback will help us improve your experience
Dheeraj Sharma and 75 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The motion of a particle of mass m is describe by y=ut + 1/2gt^2 . Find the force acting on the particle
The motion of a particle of a mass $m$ is describe by $\mathrm{y}=\mathrm{ut}+(1 / 2) \mathrm{gt}^{2}$. Find the force acting on the particle. (A) $\mathrm{F}=\mathrm{ma}$ (B) $\mathrm{F}=\mathrm{mg} \quad$ (C) $\mathrm{F}=0$ (D) None of these
A particle of mass $m$ initially at rest, is acted upon by a variable force $F$ for a brief interval of time $T$. It begins to move with velocity $u$ after the force stops acting. $F$ is as a function of time shown in the graph. The velocity o $[$ the particle is: (a) $u-\frac{\pi F_{e}^{2}}{2 m}$ (b) $u-\frac{\pi T^{2}}{8 m}$ (c) $u-\frac{\pi F_{n} T}{4 m}$ (d) $u-\frac{F_{n} T}{2 m}$
Center of Mass and Collision
Section B
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD