00:02
In this exercise, we are given that the probability is 0 .4, that a traffic fatality will involve an intoxicated or alcohol impaired driver or non -occupant.
00:13
In the first part of the problem a, we're supposed to find the probability that the number y of fatalities that involve intoxicated or alcohol impaired drivers or non -occupant is exactly 3.
00:30
At least three and at most three.
00:34
Now, before we can do that, we would need to create the probability distribution for that random variable y.
00:43
And first, y can take on the value zero all the way to 8.
00:51
Because we are looking at 8 traffic fatalities.
00:58
Write the numbers all the way to 8.
01:01
And then the next column will be for the probabilities.
01:11
You need to fill up the table with the different probabilities for different numbers.
01:15
So we use a binomial distribution formula.
01:21
The number of fatalities is 0 out of 8 trials and the success probability is 0 .4.
01:39
And we say false.
01:43
From there we copy the formula all the way through for the 8.
01:47
Different values of y.
01:50
Now we have our probabilities, probability distribution and in part a of the question we are looking at three different probabilities the first one the probability that y is exactly three that means that we're looking at y equals three and come back to the table the value is zero points so you just need to put that there 0 .278 which you can round off to make it 0 .279.
02:45
Next we're looking at the probability that the number is at least three.
02:53
So at least three means it could be three, four or four or five, six, six, 7 and 8.
03:04
So the probability that y is at least 3 will be obtained as follows.
03:26
You will have to get the probabilities for 0, 1 and 2.
03:36
Then we add them up.
03:39
And then we subtract from 1 the sum of these probabilities.
03:45
So it will be equal to 1 minus the sum...