00:01
In this problem, we have f of x as x to the power of 5 minus x cube plus 3 over x square minus 1.
00:13
Now for this problem to get the asymptotes, first we write f of x as it can be written as taking x cube common, this is x square minus 1 plus 3 over x square minus 1 or this is nothing but x cube plus, next we have this is 3 over x square minus 1.
00:43
So i can write this as x minus 1 minus x plus 1, let us write it x plus 1 and we write minus 1 here, whole divided by this is 2 x square minus 1.
01:02
So this is x cube plus 3 over 2, 1 over x minus 1 plus, next we have minus 3 over 2, 1 over x plus 1.
01:21
Now note that limit x tends to plus minus infinity, f of x minus x cube is simply 0, as this term and this term both go to 0, this means that f x, so this is my g x, so we have f x is asymptotic to g x which is x cube...