00:02
In this question, we are given this situation, so there's a link ab that rotates with an angular velocity of three radiance a second.
00:11
Then in this question we want to determine the velocity of block c and angular velocity of the link bc.
00:18
At the instance when data it goes to 45 degrees, data is this angle.
00:25
Okay, this data.
00:27
Then we need to sketch the position of link.
00:30
Bc when theta equals to 60 degrees, 45 degrees, and 30 degrees to show its general plane motion.
00:38
Okay, so let's just write down the given information.
00:43
So omega ab is 3k, radiance per second, and then we are also given that the position vector of from a to b.
00:59
It's actually 0 .5 times cosine.
01:03
45 degrees i plus sign 45 degrees j okay so using this tool we can determine vb either it's just omega ab cross rab 3k cross 0 .5 cosine 4 5 cosign 45 degrees i plus sign 45 degrees j this is 1 .5 root 2 over 2, k cross i gives j and then k cross j gives minus i.
01:53
So this is 0 .75 square root 2 minus i plus j.
02:04
Then we can use the relative velocity equation bc equals to bb plus omega bc cross r, the position of c relative to point b.
02:26
So ruby is 0 .75 root 2 minus i plus j.
02:44
Then omega bc will just be some generic omega omega and it's in the k direction then cross 1 .5 i okay so point b is here point c is here is 1 .5 meters to the right okay so it's 1 .5 i and then from the diagram vc we see has to be in the eye direction okay and it's going to be negative because as the as link ab rotates counterclockwise c is going to move to to the left.
03:27
Okay? so we just continue to do this part.
03:32
So 0 .75 square root 2 minus i plus j so 1 .5 omega bc k cross i gives j...