00:01
In this exercise, we have a tungsten target being bombarded by photons.
00:06
We're given the information that the work function of the tungsten target is given by 4 .5 electron volts.
00:16
And the photons have an energy of 4 .8 electron volts.
00:23
And in the first question, question a, we were asked, what is the threshold frequency for for the tungsten.
00:34
So we know that the threshold frequency will be the frequency that will give the the photon enough energy to remove an electron.
00:45
So that means that the energy of the photon, which is hf, will be equal to the work function theta.
00:52
I'm sorry, the work function five.
00:55
Since h, so f is going to be phi over h, phi, phi is five is.
01:04
Is 4 .5 electron volts and h is 4 .14 times 10 to the minus 15 electron volts second.
01:18
So we have the frequency as 1 .1 times 10 to the 15th hertz...