The $\pi^{\circ}$ decays electromagnetically with $\tau\left(\pi^{\circ}\right)=$ $8.7 \times 10^{-17} \mathrm{~s}$, but the $\pi^{+}$ decays only weakly with $\tau\left(\pi^{+}\right)=2.6 \times 10^{-8} \mathrm{~s}$. You can explain the large difference between these lifetimes in terms of the different ranges of the electromagnetic and weak interactions: First, recall that any meson is composed of two quarks. Next, note that, according to the electroweak theory, the intrinsic strengths of the electromagnetic and weak interactions are the same; this means that the probabilities for either kind of interaction are about the same, provided that two quarks are within the relevant range. Now the two quarks in a meson are always within the (infinite) range of the electromagnetic force; on the other hand, they are very seldom within the range of the weak force. Given that the two quarks move more or less randomly inside the volume of the meson (radius of order $1 \mathrm{fm}$ ) and that the range of the weak force is of order $10^{-3} \mathrm{fm}$, estimate what fraction of the time the two quarks are within the range required for weak interaction. Use these considerations to estimate the ratio $\tau\left(\pi^{\circ}\right) / \tau\left(\pi^{+}\right)$, and show that your answer is of the same order as the observed ratio.