Question
The plane $2 x+3 y-4 z=5$ intersects the $x$ -axis at $(a, 0,0),$ the $y$ -axis at $(0, b, 0),$ and the $z$ -axis at $(0,0, c) .$ The value of $a+b+c$ is(A) 1(B) $\frac{35}{12}$(C) 5(D) $\frac{65}{12}$(E) 9
Step 1
Since the x-axis has coordinates of the form $(x, 0, 0)$, we can plug in $y = 0$ and $z = 0$ into the equation of the plane to find the x-coordinate of the intersection point: $$2x + 3(0) - 4(0) = 5 \Rightarrow x = \frac{5}{2}$$ So the intersection point with the Show more…
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