Question
The plastic tube in Fig. 14-30 has a cross-sectional area of $5.00 \mathrm{~cm}^{2}$. The tube is filled with water until the short arm (of length $d=0.800 \mathrm{~m}$ ) is full. Then the short arm is sealed and more water is gradually poured into the long arm. If the seal will pop off when the force on it exceeds $9.80 \mathrm{~N}$, what total height of water in the long arm will put the seal on the verge of popping?
Step 1
We know that 1 m² = 10,000 cm². So, the area $A$ in m² is given by: \[A = 5.00 \, \text{cm}^2 \times \frac{1 \, \text{m}^2}{10,000 \, \text{cm}^2} = 0.0005 \, \text{m}^2\] Show more…
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The plastic tube in Fig. 14-30 has a cross-sectional area of 5.00 cm². The tube is filled with water until the short arm (of length d = 0.800 m) is full. Then the short arm is sealed and more water is gradually poured into the long arm. If the seal will pop off when the force on it exceeds 9.80 N, what total height of water in the long arm will put the seal on the verge of popping?
$\cdot 10$ The plastic tube in Fig. $14-30$ has a cross-sectional area of $5.00 \mathrm{~cm}^{2}$. The tube is filled with water until the short arm (of length $d=0.800 \mathrm{~m}$ ) is full. Then the short arm is scaled and more water is gradually poured into the long arm. If the seal will pop off when the force on it exceeds $9.80 \mathrm{~N}$, what total height of water in the long arm will put the seal on the verge of popping?
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