Question
The points of contact of the tangents drawn from $\mathrm{P}(-2,2)$ to the parabola $\mathrm{y}^{2}=16 \mathrm{x}$ are $\mathrm{A}$ and $\mathrm{B}$. Then $\mathrm{AB}$ is(a) $4 \sqrt{17}$(b) $\sqrt{5}$(c) $2 \sqrt{17}$(d) $3 \sqrt{17}$
Step 1
This can be rewritten in standard form as \( x = \frac{y^2}{16} \). Show more…
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