Question
The positions of two objects, $P_{1}$ and $P_{2}$, on a coordinate line at the end of $t$ seconds are given by $s_{1}=3 t^{3}-12 t^{2}+$ $18 t+5$ and $s_{2}=-t^{3}+9 t^{2}-12 t,$ respectively. When do the two objects have the same velocity?
Step 1
So, we first need to find the derivatives of $s_{1}$ and $s_{2}$. The derivative of $s_{1}$ is: \[v_{1} = \frac{ds_{1}}{dt} = 9t^{2} - 24t + 18\] The derivative of $s_{2}$ is: \[v_{2} = \frac{ds_{2}}{dt} = -3t^{2} + 18t - 12\] Show more…
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