At time t sec, the positions of two particles on a coordinate line are s1 = 3t3 - 12t2 + 18t + 5 m and s2 = -t3 + 9t2 - 12t m. When do the particles have the same velocities?
Added by Karen C.
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The velocity is the derivative of the position function with respect to time. For particle 1, the position function is s1(t) = 3t^3 - 12t^2 + 18t + 5. Taking the derivative with respect to time, we get: v1(t) = ds1/dt = 9t^2 - 24t + 18 For particle 2, the Show more…
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