Question
The pressure inside a tyre is $4 \mathrm{~atm}$ at $27^{\circ} \mathrm{C}$. If the tyre bursts suddenly, new temperature will be $(\gamma=7 / 5)$(a) $300(4)^{7 / 2}$(b) $300(4)^{2 / 7}$(c) $300(2)^{7 / 2}$(d) $300(4)^{-2 / 7}$
Step 1
When the tyre bursts, the final pressure $P_2$ is equal to the atmospheric pressure, which is $1$ atm. We are asked to find the final temperature $T_2$. Show more…
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Round 1
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