Question
The pressure on a sample of an ideal gas is increased from $715 \mathrm{mmHg}$ to 3.55 atm at constant temperature. If the initial volume of the gas is $485 \mathrm{mL},$ what is the final volume of the gas?
Step 1
We know that 1 atmosphere is equivalent to 760 millimeters of mercury. So, we can set up a conversion factor as follows: \[P_1 = 715 \, \text{mmHg} \times \frac{1 \, \text{atm}}{760 \, \text{mmHg}} = 0.941 \, \text{atm}\] Show more…
Show all steps
Your feedback will help us improve your experience
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The pressure on a sample of an ideal gas is increased from 715 mmHg to 3.55 atm at constant temperature. If the initial volume of the gas is 485.0 mL, what is the final volume of the gas?
A sample of gas has an initial volume of 3.95 L at a pressure of $705 \mathrm{mm}$ Hg. If the volume of the gas is increased to $5.38 \mathrm{L}$ what is the pressure? (Assume constant temperature.)
A sample of gas has an initial volume of $3.95 \mathrm{~L}$ at a pressure of $705 \mathrm{~mm} \mathrm{Hg}$. If the volume of the gas is increased to $5.38 \mathrm{~L}$, what is the pressure? (Assume constant temperature.)
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD