00:03
In this question, we are asked to identify the structure that gives rise to the given nmr spectrum.
00:13
And we also told that the molecule that corresponds to the given nmr spectrum has a molecular formula c7h14o.
00:26
So we see that there are twice as much as hydrogens compared to the number of carbons.
00:32
So we have this formula.
00:38
And if we only have twice as much as hydrogens instead of 2n plus 2, where n is the number of carbons, it means that there is a single iron saturation that caused two hydrogens to go missing in the structure.
01:01
So let's keep in mind that there's a, there's probably a double bond.
01:07
Or a cycle in the structure.
01:11
So if we take a look at the nmr spectrum, we see that there's a peak near 210 ppm.
01:22
So that c13 nmr spectrum peak is usually from a carbonyl group.
01:36
A peak near 210 is observed in a c13 nmr spectrum from a carbonal group.
01:43
A carbonyl group.
01:45
So let's also keep in mind that we have a carbonyl group.
01:50
So if we had an unsaturation, that unsaturation could be coming from the carbonyl group and then, so it's pretty much the same thing that we figured out in the two first points that i just mentioned.
02:08
So also we see that there are only three peaks in the spectrum out of which, one is for the carbonyl group.
02:20
So that tells us that there are only three types of carbons in this molecule.
02:26
So the other two peaks besides the carbonyl peak are much upfield in the spectrum and one of them is a doublet and the other one is a quartet.
02:41
So the doublet should most probably be coming from a ch group.
02:50
So that n plus 1 is 1 plus 1 equals 2...