Question
The radius of curvature of the curve $y=e^{x}$ at the point where it crosses the $y$-axis is(a) 2(b) $\sqrt{2}$(c) $2 \sqrt{2}$(d) $\frac{1}{2} \sqrt{2}$.
Step 1
This happens when $x=0$. Substituting $x=0$ into the equation, we get $y=e^0=1$. So, the curve crosses the y-axis at the point $(0,1)$. Show more…
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