The rate law for a reaction between the substances $\mathrm{A}$ and is given by Rate $=[\mathrm{A}]^{\mathrm{n}}[\mathrm{B}]^{\mathrm{m}}$ :
On doubling the concentration of $\mathrm{A}$ and halving theconcentration of $\mathrm{B}$, the ratio of the new rate to the earlier rate of the reaction will be as
(a) $1 / 2^{(\mathrm{m}+\mathrm{m})}$
(b) $(\mathrm{m}+\mathrm{n})$
(c) $(\mathrm{n}-\mathrm{m})$
(d) $2^{(n-m)}$