00:01
Hi there.
00:02
In this problem, we are given a rather lengthy balanced equation.
00:08
So let me get that written down here.
00:11
We have 2kmn -o -4, reacting with 16 hydrochloric acid, and it produces 2m -n -cl2 plus 5 chlorine gases plus 8.
00:46
H20 and 2 kcl.
00:57
And we would like to be able to produce 9 .81 liters of the kcl.
01:07
What we want to know is how many grams of the kmno4 we have to begin with to produce this many liters of kcl, i'm sorry, of cl2 at standard temperature and pressure.
01:22
So let's think about what we need to do here.
01:24
We're going to have to start with what we know, which is the liters of cl2.
01:31
Since this is at standard temperature and pressure, we can use the molar volume of 22 .4 to convert two moles of cl2.
01:40
Then we can use the mole ratio in this balanced equation to go from moles of cl2 to moles of kmno4.
01:47
And then finally, we can multiply by the molar mass of kmno4 to give us grams.
01:53
So that's our plan.
01:54
Let me go ahead.
01:55
And write down the actual steps now.
01:58
We have to start with what is given...