00:01
I was asking us about a situation where there's natural selection acting against the small a allele, that's the homosigous recessive.
00:08
So we need two equations because we're asked to find the frequency in a in the next generation.
00:14
And so that's going to be p prime.
00:15
So that'll be the frequency of big a in the next generation.
00:18
Equals p times p with the fitness of the homosigous dominant plus q times the heterocygous fitness.
00:28
And all of that divided by the average fitness.
00:33
Now, so obviously we need to have the average fitness.
00:36
And average fitness is simply p squared times the fitness plus 2pq times the heterozygous fitness and q squared times the homozygous recessive fitness like that.
00:55
And that's the way to calculate the average fitness.
00:58
And so we'll need this to plug into that.
01:00
So let's do that first.
01:02
We just have to plug our numbers in here.
01:06
So it's 0 .5.
01:09
That's what we get from the question squared times one.
01:12
That's the fitness of the homozygous dominant plus two, that two right there, times 0 .5.
01:19
Again, the frequency of p and q are both 0 .5 in this equation.
01:23
And then the heterozygous fitness is 1 .0.
01:27
And then finally we get to the q squared.
01:31
Which is 0 .5, and that's the frequency of the q allele squared, and then the fitness here.
01:37
And that was 0 .7.
01:38
So that's where we see the decrement of loss of fitness.
01:42
So if you do all of that math, and if i did it correctly, you get a value of 0 .925.
01:49
So we take that number and put it in there.
01:52
So that means that p prime equals 0 .5, and that's this p, and that's going to be times.
02:02
I think i'll put a bracket here to make this clearer.
02:06
0 .5 times the fitness, the average fitness, which is one, or not the average fitness, but the fitness of the hummus zygd dominant...