00:02
We're told to have a rotor and an electric motor, and we're given the following quantities about the rotor.
00:10
Part a of the problem is asking us to find what maximum torque can act on the rotor.
00:20
And the equation for torque is equal to the number of turns in a coil of wire n times the area a, times the magnetic field b, and then times the current i.
00:42
And these are all values that are given to us by the problem.
00:47
So we can just plug them in.
00:49
So we plug in m and we plug in a, we plug in b, and then we plug in, and then this will give us a torque.
01:13
That is equal to 6 .40 times 10 to the negative 4 newton meters.
01:36
Now in part b, we need to calculate the peak power output, and we know that power is equal.
01:47
Power is equal to torque times the angular velocity.
01:59
So the torque we calculated in the previous part, so we can just plug in torque, which was 6 .4 times 10 to the negative 4 nanometers, and the angular velocity was given to us by the problem, and we just need to convert it to radiance per second.
02:23
So this is going to be 3 .60 times 10 to the 3 .3.
02:30
Revolutions per minute, and then to convert it to radiance per second, we do 2 pi, 2 pi radiance, divide by one revolution times one minute divided by 60 seconds.
02:53
And so this will give us a power that is equal to 0 .2 41 watts.
03:11
Now for part c, we need to calculate the amount of work performed by the magnetic field onto the rotor...