Question
The sewage outlet of a house constructed on a slope is 6.59 $\mathrm{mbe}$ low street level. If the sewer is 2.16 $\mathrm{m}$ below street level, find the minimum pressure difference that must be created by the sewage pump totransfer waste of average density 1000.00 $\mathrm{kg} / \mathrm{m}^{3}$ from outlet to sewer.$+70 \mathrm{pC}$ and $-70 \mathrm{pC}$ , which result in a 20 $\mathrm{V}$ potential differencebetween them. (a) What is the capacitance of the system? (b) If thecharges are changed to $+200 \mathrm{pC}$ and $-200 \mathrm{pC}$ what does the capac-itance become? (c) What does the potential difference become?
Step 1
In mathematical terms, this is expressed as $C = \frac{Q}{\Delta V}$. Here, we have a charge of $70 \, pC$ and a potential difference of $20 \, V$. Substituting these values into the formula gives us the capacitance of the system. Show more…
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The sewage outlet of a house constructed on a slope is 6.59 $\mathrm{mbe}$ - low street level. If the sewer is 2.16 $\mathrm{m}$ below street level, find the minimum pressure difference that must be created by the sewage pump to transfer waste of average density 1000.00 $\mathrm{kg} / \mathrm{m}^{3}$ from outlet to sewer.
The sewage outlet of a house constructed on a slope is $6.59 \mathrm{~m}$ below street level. If the sewer is $2.16 \mathrm{~m}$ below street level, find the minimum pressure difference that must be created by the sewage pump to transfer waste of average density $1000.00 \mathrm{~kg} / \mathrm{m}^{3}$ from outlet to sewer.
The scwage outlet of a house constructed on a slope is $6.59 \mathrm{~m}$ below street level. If the sewer is $2.16 \mathrm{~m}$ below street level, find the minimum pressure difference that must be created by the sewage pump to transfer waste of average density $1000.00 \mathrm{~kg} / \mathrm{m}^{3}$ from outlet to sewer.
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