The formula for the Moment of Inertia for a circular shaft is given by:
\[I = \frac{\pi}{4} (D_{\text{outer}}^4 - D_{\text{inner}}^4)\]
Substituting the given values into the formula, we get:
\[I = \frac{\pi}{4} (10.3^4 - 40.3^3^4) = 0.4375 \times 10^6 \,
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