00:01
In this question it is given that there is a 61 semi -diameter wheel that is accelerating uniformly about its center from 120 revolutions per minute to 280 revolutions per minute in 4 seconds.
00:12
Now we have to find the angular acceleration and the radial and tangential component of the linear acceleration of a point on the age of the wheel after 2 seconds.
00:24
So first of all i am writing the given data for this question.
00:27
So we have given diameter that is 61 semi -semi.
00:32
Or i can say this is 0 .61 meter.
00:37
Now radius is given by that is 61, sorry, 0 .61 by 2 and this will come out to be 0 .305 meter this is the radius.
00:46
We have given the initial issue that is omega 1 is equal to 120 revolutions per minute or i can say this is 120 into 2 pi by 60 so this will come out to be 12 .56 radiance per second we have given the final speed that is omega 2 is equal to 280 revolutions per minute.
01:09
So this is 280 into 2 pi by 60 and this will come out to be 29 .3 to radian per second.
01:20
We have given the time that is delta t is equal to 4 second.
01:24
Now in the first part of the problem we have to find the angular acceleration.
01:31
So we can see that angular acceleration is given by the second...