Question
The stress-strain diagram for a steel alloy having an original diameter of 0.5 in. and a Gage length of 2 in. is given in the figure, Determine approximately the modulus of elasticity for the material, the load on the specimen that causes yielding and the ultimate load the specimen will support.
Step 1
Using the formula $\Delta = 200 \tan(\alpha)$, we find the displacement for point A to be $\Delta_A = 2 \times 200 = 6.98$ mm. Similarly, for point C, $\Delta_C = 10.47$ mm and for point D, $\Delta_D = 17.46$ mm. Show more…
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