We have the static pressure to stagnation pressure ratio \( \frac{P}{P_0} = 0.6 \) and the stagnation temperature \( T_0 = 20^{\circ} \mathrm{C} \). Convert the stagnation temperature to Kelvin:
\[
T_0 = 20 + 273.15 = 293.15 \, \text{K}
\]
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