Question
The sum of first 9 terms of the series $\frac{1^{3}}{1}+\frac{1^{3}+2^{3}}{1+3}+\frac{1^{3}+2^{3}+3^{3}}{1+3+5}+\ldots . .$ is:(A) 96(B) 142(C) 192(D) 71
Step 1
The series is given as: \[ \frac{1^{3}}{1} + \frac{1^{3}+2^{3}}{1+3} + \frac{1^{3}+2^{3}+3^{3}}{1+3+5} + \ldots \] The \(n\)-th term can be expressed as: \[ T_n = \frac{1^3 + 2^3 + \ldots + n^3}{1 + 3 + 5 + \ldots + (2n-1)} \] Show more…
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