00:03
Here we have co, co2, and c3o2.
00:12
For co, the number of balanced electrons is 4 plus 6, 10.
00:20
The lowest structure for co, we first write out the atoms, then we try to complete the octets on each atom.
00:31
So if they were to shed six electrons and have two long, bears on them then the complete number of electrons would be 10 so if you want to write it this way you can do that too don't forget the long pairs on the carbon and the oxygen for the molecular structure it's linear and the hybridization which we can easily calculate the hybridization of the central atom which in this case we're considering it to be carbon is zero minus zero plus zero and 4 divided by 2, 2 is sp.
01:20
So when you write it out, your carbon that has the sp hybridization has one lone pair and the other orbital overlaps with the p orbital of oxygen to form a sigma bond.
01:37
And the other two p orbitals overlap with the p orbitals of oxygen to form 2 pi bonds.
01:48
So this is one pi bond and in the axis that's perpendicular to the first set of pibein, you have the second pi bond.
02:06
For co2, the number of balance electrons is 4 plus 6 into 2, that's 12, so 16.
02:17
The way we draw the lewis structure is we try to complete the octet around each atom.
02:24
So if carbon and oxygen were to share four electrons each and oxygen were to have two known pairs on it we could complete the octet configuration also written as this molecular structure is obviously linear...