00:01
Okay, so this problem is a two -slit problem.
00:03
We can say d is equal to 0 .35 meters.
00:09
It gives us the frequency of the sound wave, so it's going to be 2 ,000 hertz, and then the velocity of the sound is 340 meters per second.
00:25
We can use that to get our wavelength by just doing velocity divided by frequency.
00:30
So it's going to be 0 .17 meters.
00:34
And so we're going to get, we can use the formula to find the bright fringes.
00:39
Of 0 .35 times sine theta equals m times 0 .17.
00:50
And so because sine theta has to be between negative 1 and positive 1, that means when we plug in our m values, we're only going to get, because 0 .17 divided about 0 .35, it's close to a half, a little bit less than a half...