Question
The value of $(1+i)^{3}+(1-i)^{6}$ is(a) $10-2 \mathrm{i}$(b) 2(c) $\frac{(1-5 i)}{\sqrt{2}}$(d) $-2+10 \mathrm{i}$
Step 1
So, we can write $(1+i)^{3}$ as $(1+i)^{2}*(1+i)$. Now, let's expand $(1+i)^{2}$. \begin{align*} (1+i)^{2} &= 1^{2} + 2*1*i + i^{2} \\ &= 1 + 2i - 1 \\ &= 2i \end{align*} So, $(1+i)^{3} = 2i*(1+i) = 2i + 2i^{2} = 2i - 2$. Show more…
Show all steps
Your feedback will help us improve your experience
Anas Venkitta and 70 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The value of $(1+i)^{3}+(1-i)^{6}$ is (a) $10-2 \mathrm{i}$ (b) 2 (c) $\frac{(1-5 i)}{\sqrt{2}}$ (d) $-2+10 \mathrm{i}$
The value of $\left(\frac{-1+i \sqrt{3}}{1-i}\right)^{30}$ is (a) $-2^{15}$ (b) $2^{15} i$ (c) $-2^{15} i$ (d) $6^{5}$
The value of $(1+i)^{8}-(1-i)^{8}$ is (a) 0 (b) 16 (c) 32 (d) $\sqrt{2}(1+i)$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD