Question
The value of $(1+i)^{8}-(1-i)^{8}$ is(a) 0(b) 16(c) 32(d) $\sqrt{2}(1+i)$
Step 1
We have \begin{align*} (1+i)^2 &= 1^2 + 2i + i^2 = 1 + 2i - 1 = 2i, \\ (1-i)^2 &= 1^2 - 2i + i^2 = 1 - 2i - 1 = -2i. \end{align*} Show more…
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