Question
The value of $\int_{0}^{18 \log (1+x)}{1+x^{2}} d x$ is(a) $\frac{\pi}{8} \log 2$(b) $\frac{\pi}{2} \log 2$(c) $\log 2$(d) $\pi \log 2$
Step 1
To evaluate this integral, we first need to determine the limits of integration. The upper limit is \( 18 \log(1+x) \). Show more…
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