00:01
In this question, we need to evaluate the limit, that is limit extends to 1 over the expression x cube plus 2x squared plus 1 over x squared plus 2x plus 3 and whole to the power 1 minus cosine x minus 1 over x minus 1 whole square.
00:18
So on substituting x is 1, we get 5x6 to the power infinite.
00:25
So this is indeterminate form.
00:27
So now we will change some terms in this expression.
00:32
So we will get limit x tends to 1.
00:38
And here, x cube plus 2x square plus x plus 1 over x square plus 2x plus 1.
00:54
And here in the exponent, that is 1 minus cosine x minus 1 can be written as 2, sum.
01:01
Square x minus 1 over x minus 1 whole square so 2 sine square x minus 1 by 2 the identity says that is 1 minus cosine theta can be written as 2 sine square theta by 2 therefore this will become in the power that is 2 sine square x minus 1 over 2 over x minus 1 whole square now we will change this we can write it as limit we can evaluate the limit over this expression, that is in the base, and we will take this limit to the power.
01:55
So this will become actually, here substituting x as 1...