We can rewrite the limit as $\lim _{x \rightarrow 0}\left(\frac{e^{x \ln \left(2^{x}-1\right)}-\left(2^{x}-1\right)^{x} \sin x}{e^{x / n x}}\right)^{1 / x}$ as $\lim _{x \rightarrow 0}\left(\frac{\left(2^{x}-1\right)^{x}-\left(2^{x}-1\right)^{x} \sin
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