Question
The voltage applied to a circuit is $12.0 \mathrm{V}$ when the current through the battery is 0.858 A. If the internal resistance of the battery is $0.245 \Omega,$ what is the emf?
Step 1
This can be written as: \[ V = E - Ir \] where \( V \) is the potential difference, \( E \) is the emf, \( I \) is the current, and \( r \) is the internal resistance. Show more…
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