00:01
In this question, it is about photoelectric effect.
00:04
So you have a material.
00:08
The work function is 3 .5 ev.
00:14
And the light that's shining on the material is 300 nanometers.
00:20
You want to find the stopping potential and the color frequency.
00:25
So to find the stopping potential, we'll be using the photo -electric effect equation.
00:44
So kmax equals to hf minus 5 and then this is equal to ev0.
00:54
So we first find hf, okay, hf equals to hc over lambda.
01:03
So you put in all the numbers.
01:16
Then you calculate this to be, okay, want to calculate the energy.
01:22
Okay, you get 6 .63 times 10 to the negative 19 jews.
01:40
You convert this into ev and we get 4 .14 ev...