Question

The work function of potassium is $3.68 \times 10^{-19} \mathrm{~J}$. (a) What is the minimum frequency of light needed to eject electrons from the metal? (b) Calculate the kinetic energy of the ejected electrons when light of frequency equal to $8.62 \times 10^{14} s^{-1}$ is used for irradiation. 

   The work function of potassium is $3.68 \times 10^{-19} \mathrm{~J}$. (a) What is the minimum frequency of light needed to eject electrons from the metal? (b) Calculate the kinetic energy of the ejected electrons when light of frequency equal to $8.62 \times 10^{14} s^{-1}$ is used for irradiation.
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Chemistry
Chemistry
Raymond Chang, Jason… 14th Edition
Chapter 7, Problem 21 ↓
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The work function of potassium is $3.68 \times 10^{-19} \mathrm{~J}$. (a) What is the minimum frequency of light needed to eject electrons from the metal? (b) Calculate the kinetic energy of the ejected electrons when light of frequency equal to $8.62 \times 10^{14} s^{-1}$ is used for irradiation.
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Transcript

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00:01 Question 21.
00:02 The work of potassium 3 .68, 10, 19, jow.
00:08 So the question a is, what is the minimum of light? the minimum of frequency of light.
00:20 The minimum of frequency of light.
00:34 Frequency of light.
00:42 Needed to eject electrons from the metal if we suppose the kinetic energy, did the to eject electron from the middle of the minimum frequency of light equals 0? we should have k -e.
01:02 We have h -new equal k -e plus work.
01:10 If we want to find the minimum of light frequency to reject electron from the meter, we set k -e equals 0 so the equation turn 2 has nu equal double use so it should be 6 .63 tie 10 negative 34 joe second and new equal 3 .68 tie 10 negative 19 joe so solve the problem we see you should be 3 .6 , 6 .6...
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