00:01
Okay, so in this situation we have a mirror, but we're going to treat this mirror as a lens.
00:09
And there's our image plane here.
00:14
And we know that there's a cyclist behind our mirror that's 1 .5 meters tall and 25 meters away.
00:23
And we ourselves are one meter away.
00:27
And the lens has a focal length of negative 0 .8 meters.
00:35
Okay, so for part a, we want to know where the image of the cyclist is.
00:44
Where is the image of the cyclist relative to the person? okay, so that's going to be our standard 1 over f equals 1 over do plus 1 over d .i, which is going to become 1 over negative 0 .8 equals distance the object.
01:05
It's cyclist 25 meters plus 1 over d .i.
01:13
And d .i is going to come out to be 0 .77 or negative 0 .77.
01:20
So i drew this out as a lens just to keep this clear, but really it's a mirror.
01:25
So how it would look is here's a mirror, here's the driver right here, one meter away.
01:34
And then the driver's going to look at the mirror.
01:36
And then the image, the cyclist is back here, right? looks at the mirror and then reflects back.
01:43
But i think this is a little bit easier of a way to visualize it.
01:47
Okay.
01:48
And, okay, so to answer the question how far we are, we are.
01:56
Okay, so the cyclist is going to be negative 0 .77 away from the mirror.
02:01
So that would actually be in this diagram on this side.
02:07
But if there's a mirror, they'd appear to be.
02:09
So here's our mirror...