00:01
We're going to talk about length contraction.
00:02
So consider that we have an object that has a proper length, l, meaning that this is the length as measured in the reference ring where the object is at rest.
00:15
And imagine that this object is moving with a speed v relative to an observer.
00:21
I'm going to call this observer s.
00:26
So what special relativity tells us is that the length as measured by an observer that is at rest, relative to reference frame s is equal to the proper line divided by gamma, where gamma is 1 over a square root of 1 minus v squared over c squared.
00:47
And what the exercise tells us is that there is a plane that broke the record for the fastest aircraft that exists.
01:00
And this plane travels with a speed of 2 ,00020.
01:05
And 20 meters per second.
01:09
And our goal is to find out by how much the length of this aircraft contracted when it's traveling at this speed relative to an observer at rest in the earth.
01:25
Okay, so all we have to do is to use this formula that i wrote here.
01:34
So let's do it.
01:35
And we have to use this formula, but we also have to notice that v over c, that is 2 ,020 divided by 3 times 0 .8, is much smaller than 1.
01:48
So there is an approximation that we can use.
01:51
What i'm going to do is to use the approximation that 1 minus x to the n is approximately 1 minus an x as long as x is much smaller than 1.
02:02
And i'm writing this because notice the gamma can be written, i'm going to write it here.
02:10
Gamma is 1 minus v squared over c squared to the minus 1 half...