Question
The $y$ - coordinate of one focus of the ellipse $36 x^{2}+25 y^{2}+144 x-50 y-$$731=0$ is(A) $-2$(B) 1(C) 3.32(D) 4.32(E) 7.81
Step 1
The given equation is $36x^{2}+25y^{2}+144x-50y-731=0$. We can rewrite this as $(36x^{2}+144x)+(25y^{2}-50y)=731$. Show more…
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The centre of the ellipse $\frac{(x+y-2)^{2}}{9}+\frac{(x-y)^{2}}{16}=1$ is at (a) $(1,1)$ (b) $(2,0)$ (c) $(0,2)$ (d) $(0,0)$
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Ellipses
Match each equation of an ellipse in Column I with the appropriate intercepts in Column II. $\mathbf{I}$ (a) $36 x^{2}+9 y^{2}=324$ (b) $9 x^{2}+36 y^{2}=324$ (c) $\frac{x^{2}}{25}+\frac{y^{2}}{16}=1$ (d) $\frac{x^{2}}{16}+\frac{y^{2}}{25}=1$ $\mathbf{I I}$ A. $(-3,0),(3,0),(0,-6),(0,6)$ B. $(-4,0),(4,0),(0,-5),(0,5)$ C. $(-6,0),(6,0),(0,-3),(0,3)$ D. $(-5,0),(5,0),(0,-4),(0,4)$
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