Question
The centre of the ellipse $\frac{(x+y-2)^{2}}{9}+\frac{(x-y)^{2}}{16}=1$ is at(a) $(1,1)$(b) $(2,0)$(c) $(0,2)$(d) $(0,0)$
Step 1
The center of the ellipse is obtained by setting the terms inside the squares to zero. Show more…
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