Question
The centre of the ellipse $17 x^{2}-12 x y+8 y^{2}+46 x-28 y+17=0$ is at(a) $(1,1)$(b) $(-1,1)$(c) $(-1,-1)$(d) $(1,-1)$
Step 1
The general equation of an ellipse is $Ax^{2}+By^{2}+2Hxy+2Gx+2Fy+C=0$. Comparing the coefficients of the given equation with the general equation, we get $A=17$, $B=8$, $H=-6$, $G=23$, $F=-14$ and $C=17$. Show more…
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