There are $n$ white and $n$ black balls marked 1,2, $\cdots, n$. The number of ways in which we can arrange these balts in a row so that neighbouring balls are of different colours is
(a) $n !$
(b) $(2 n) !$
(c) $2(n)^{2}$
(d) $\frac{(2 n) !}{(n !)^{2}}$.