00:01
Okay, so the first thing to do in this problem is to find our d.
00:04
So since we have one centimeter, and there's 3 ,660 slits per centimeter, we can divide that and see that the distance between each slit is going to be around 2 ,732 nanometers.
00:31
Okay, so for part a, we have 10 .1 degrees.
00:39
We're given 13 .7 degrees and we're given 14 .8 degrees is where the spectral lines occur.
00:50
So we're just going to do d times sine of those status and i'll give us the wavelength of the light.
00:57
So d times sign of that angle.
01:01
So d we just found as 2732 nanometers times sign of 10 .1 degrees.
01:07
That's going to give us a wavelength of 479 nanometers.
01:16
For 13 .77.
01:17
Degrees, we're going to get a wave length of 647 nanometers.
01:38
And for 14 .8 degrees, we're going to get 697 or 698 nanometers rounded up.
01:55
Okay.
01:55
And then part b wants us to do a second order.
01:59
It wants us to find the angles for those...