Question
Titration of a $12.0 \mathrm{~mL}$ solution of $\mathrm{HCl}$ requires $22.4 \mathrm{~mL}$ of $0.12 \mathrm{M} \mathrm{NaOH}$. What is the molarity of the HCl solution?
Step 1
This means that the moles of $\mathrm{HCl}$ are equal to the moles of $\mathrm{NaOH}$. We can write this as: \[M_{\mathrm{HCl}} \times V_{\mathrm{HCl}} = M_{\mathrm{NaOH}} \times V_{\mathrm{NaOH}}\] Show more…
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Titration of a 12.0 mL solution of HCl requires 22.4 mL of 0.12 M NaOH. What is the molarity of the HCl solution?
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