Question
What is the molarity of a solution of $\mathrm{HCl}$ if $10.00 \mathrm{~mL}$ is titrated with $40.2 \mathrm{~mL}$ of a $0.5 \mathrm{M} \mathrm{NaOH}$ solution?$$\mathrm{HCl}(a q)+\mathrm{NaOH}(a q) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{NaCl}(a q)$$
Step 1
We do this by dividing the volume in milliliters by 1000. $$ V_{NaOH} = \frac{40.2 \, mL}{1000} = 0.0402 \, L $$ Show more…
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