00:01
Hello.
00:03
We are given a position function.
00:07
This is in the two -dimensional case of r2.
00:11
The position function is a vector function of t in component form, four sign t, and the same component is two cosine t.
00:28
2 cosine t on an interval for the 0 to 2 pi 2 questions 1 is it does it lie on a circle if it does the radius and secondly we have to show that the velocity vector is orthogonal to the position vector which is defined with dot product being zero.
01:13
Okay, in an xy plane, if we have the vector rt, the terminal point of each vector is some point xy, so we take x and y to be these two, and the trajectory is going to be wherever these vectors are pointing four values of t from 0 to 5.
01:44
Okay, circle centered at the radius has an equation x squared plus y squared equals r squared and our first job is to find out whether the points xy satisfy this thing here.
02:03
So squaring x, squaring y, we obtain 16 sine squared t plus 4 cosine square t and we can write the 16 sine squared as 12 sine square t plus 4 sine square t and we add the four cosine squared here in order to extract four a factor out four here this will be sine squared t plus cosine squared of t 12 sine squared pythagorean no actually this was a plus and this was a t sine square of t plus cosine square of t is the fundamental pythagorean equation identity this equals 1 so x squared plus y squared is not constant it changes depending on t.
03:42
So it's 12 sine squared t plus 4 which is not equal to some radius.
03:55
So this here is what is this is probably an ellipse but it's not a circle...