Two 1.20-m nonconducting rods meet at a right angle. One rod carries +2.50 of charge distributed

step 1 in this question, we have to, uh, charge non conducting rods. Okay. And then they carry 2.5 micr

Two 1.20-m nonconducting rods meet at a right angle. One rod...

Two 1.20-m nonconducting rods meet at a right angle. One rod carries $+$2.50 $\mu$C of charge distributed uniformly along its length, and the other carries $-$2.50 $\mu$C distributed uniformly along it ($\textbf{Fig. P21.87}$). (a) Find the magnitude and direction of the electric field these rods produce at point $P$, which is 60.0 cm from each rod. (b) If an electron is released at $P$, what are the magnitude and direction of the net force that these rods exert on it?

Transcript

00:01 In this question, we have to, uh, charge non conducting rods.

00:05 Okay.

00:06 And then they carry 2.5 micro coloma charges.

00:11 It is that one of them is positive.

00:13 The other one is negative.

00:14 Okay, then we want to find a magnitude and direction of, uh, electric view at point p.

00:21 And then, um then the distance is 60 cm 82 60 cre this is also sixties year.

00:31 Okay? and after that, if you place our electron, uh, at p, if you reduce the electronic key, we want to find a magnitude and direction of that force.

00:45 Okay? exactly.

00:48 Okay.

00:48 So to do a me first, we need to draw the electric fuel due to each broad at pointy.

00:58 So, due to the positive one pointing down u to the negative one point into the left.

01:05 Okay.

01:06 And since they are equal distance okay, so we expect this to e plus and the minus to be of the same magnitude and then since the 90 degrees and, uh, downtown cookie at a 45 degree angle and below the horizontal.

01:23 Hey, so, um yeah, and the manager will just be squared.

01:30 Two of one of them.

01:31 Okay, because you can use.

01:33 You can calculate it using my degree.

01:34 Sterile.

01:36 Okay, so after doing the analysis will be using, ah, the electric field due to a charge.

01:45 Run then.

01:47 And this is good to one of her for pipes are not q over x square root x square pass.

01:55 Uh, square.

01:57 Okay, so the a e s, uh, 0.6 m.

02:06 Okay.

02:06 And then the x is also 0.6 m.